(PHP 5 >= 5.2.0, PHP 7, PHP 8)
pg_field_table — Returns the name or oid of the tables field
pg_field_table() returns the name of the table that field
belongs to, or the table's oid if oid_only is true.
resultPgSql\Result 实例，由 pg_query()、pg_query_params() 或者 pg_execute()（等）返回。
fieldField number, starting from 0.
oid_only
By default the tables name that field belongs to is returned but
if oid_only is set to true, then the
oid will instead be returned.
On success either the fields table name or oid, 或者在失败时返回 false.
| 版本 | 说明 |
|---|---|
| 8.1.0 |
现在 result 参数接受 PgSql\Result
实例，之前接受 资源(resource)。
|
示例 #1 Getting table information about a field
<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
$res = pg_query($dbconn, "SELECT bar FROM foo");
echo pg_field_table($res, 0);
echo pg_field_table($res, 0, true);
$res = pg_query($dbconn, "SELECT version()");
var_dump(pg_field_table($res, 0));
?>
以上例程的输出类似于：
foo 14379580 bool(false)
注意:
Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.